Using Can and Be Able to to Speak About Abilities

Can and Be able to are both used to speak about abilities, and the possibility of doing something. Can and Be able to are known as modal verbs in English. Here are some examples of can and be able to used to speak about abilities. Can for Abilities She can play tennis.They could speak English at a very young age.Peter can type 100 words per minute. Be Able to for Abilities My sister is able to run a marathon.The students were able to get an A on the test.We will be able to attend the class next semester. Here are examples of the two forms to speak about possibilities. Can for Possibilities Can you come to the party next week?Do you think he can help with my homework?Peter told me he could pick you up at the airport. Be Able to for Possibilities We werent able to get tickets to the concert.Shell be able to study for the test tomorrow.Jack wont be able to come for another three days. Listed below are examples and explanations for can/could/be able to for ability and permission in the past, present. and future. Examples Usage He can play tennis well.She is able to speak five languages.They can come on Friday.Jack will be able to come next week. Use can or be able to to express an ability or possibilityNOTE: The future of be able to is will be able to He could swim when he was five. Could in the past means the general ability to do something. They were able to get tickets for the concert.I was able to finish before 6.I couldnt come last night, sorry. OR I wasnt able to come last night, sorry. IMPORTANT: If someone was in the position to do something, or managed to do something, we use was/were able to instead of couldIn the negative, wasnt able to OR couldnt are both correct. Note: Can is also often used to ask for permission, as well as may: Can I come with you? May I come with you? Practice Can/Be Able To Practice can and be able to with this role play. Once youve finished, make up some of your own dialogues and practice with a classmate or a friend.   Peter: Hi Janet. Can you help me for a moment?Janet: Sure, whats up? Peter: Im not able to understand this math problem.  Janet: Really. I think I can help, but Im not that good at math. Peter: You were able to all the problems last semester, werent you?Janet: Yes, thats right, but I cant do everything. Let me see.   Peter: Here you go.Janet: Interesting, are you sure youre not able to do this? Peter: Yes, thats why Im asking for help!Janet: OK. After I explain this, youll be able to do without any problems. Peter: Great. So whats the answer?!Janet: Dont be in a hurry. Can I have a few minutes to think? Peter: Of course you can. Sorry.  Janet: No problem.

Home Depot Data Breach - 2954 Words

Home Depot Data Breach Background on the 2014 Home Depot Data Breach Home depot was the target of a cyberattack on their information system infrastructure that lasted from April of 2014 to September of 2014. As a result of the attack and following data breach, 56 million credit-card accounts and 53 million email addresses were stolen. (â€Å"Home Depot Hackers Exposed 53 Million Email Addresses†) The cyberattack involved several steps. First, the attackers gained third party credentials allowing them into the system. Next they exploited an unknown weakness in the system that allowed for the attackers to elevate their own access privileges. Finally, they installed malware on Home Depot’s self-checkout systems in the U.S. and Canada, allowing†¦show more content†¦The costs that the company will incur can be broken down into six different categories: investigation and remediation, notification, identify theft and credit monitoring, disruptions in normal business operations, and lost business. Investigation costs involve those relat ed to examining how and why the data was compromised, and remediation costs relate to the costs incurred to set up safeguards. Home Depot’s pre-tax expense relating to investigation and remediation was $43 million in the third quarter of 2014 alone. Notification costs relate to notifying the relevant individuals, regulators, and media personnel. Simply mailing notification letters, at 49 cents per stamp, equates to a $27.44 million expense. Costs relating to identify theft and credit monitoring include the cost of identity theft protection for each of the victims. Assuming $10 per victim, this results in a $560 million cost for Home Depot. Disruptions to Home Depot’s normal business operations include the opportunity cost of the reduced investments in the company’s operations, as well as reduced time on standard business activities. This cost is estimated to be $20 per victim. Home Depot will likely lose business due to customers being scared away, and the relat ed cost is approximately $30 per victim. Finally, lawsuits relating to the data breach are expected to incur $3 billion in expenses for Home Depot. 44 suits have already surfaced since the cyberattack. (â€Å"Home Depot: WillShow MoreRelatedThe Home Depot Data Breach3056 Words   |  13 PagesThe Home Depot-Data Breach Abstract The Home Depot, the home improvement, construction products and services retailer got hit by hackers by compromising the millions of customer’s data. The data of credit cards and debit cards have been stolen by the hackers. 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After Getting the credit card facility ,it has

Fan Cart Lab Conclusion free essay sample

We did a fan cart for our physics class the other day. To set up the lab first, we measured the effect of the mass of the fan cart on the acceleration of the cart. The mass of the fan cart was the independent variable and acceleration was the dependent variable. We kept the speed of the cart on medium, and calculated the acceleration and motion. As a result, we had figured out that the bigger the mass the slower the acceleration, as we all should have known. To calculate this we used the second law of Newton (F=ma). For the first experiment we got . 233 (m/s/s) with a percent error of 76%. The relationship for the first experiment was inverse because the acceleration was decreasing every time the weight (mass) increased. In the second experiment we got 3. 52 (m/s/s) with a percent error of 56. 4%. For this experiment the relationship was linear because the mass was increased for each trial. We will write a custom essay sample on Fan Cart Lab Conclusion or any similar topic specifically for you Do Not WasteYour Time HIRE WRITER Only 13.90 / page Some errors that could have taken place would be, cart alignment, track damaged, placement of the motion sensor. These can affect the data because it will give a greater percentage error. ?Fan Cart Lab We did a fan cart for our physics class the other day. To set up the lab first, we measured the effect of the mass of the fan cart on the acceleration of the cart. The mass of the fan cart was the independent variable and acceleration was the dependent variable. We kept the speed of the cart on medium, and calculated the acceleration and motion. As a result, we had figured out that the bigger the mass the slower the acceleration, as we all should have known. To calculate this we used the second law of Newton (F=ma). For the first experiment we got . 233 (m/s/s) with a percent error of 76%. The relationship for the first experiment was inverse because the acceleration was decreasing every time the weight (mass) increased. In the second experiment we got 3. 52 (m/s/s) with a percent error of 56. 4%. For this experiment the relationship was linear because the mass was increased for each trial. Some errors that could have taken place would be, cart alignment, track damaged, placement of the motion sensor. These can affect the data because it will give a greater percentage error. ?Fan Cart Lab We did a fan cart for our physics class the other day. To set up the lab first, we measured the effect of the mass of the fan cart on the acceleration of the cart. The mass of the fan cart was the independent variable and acceleration was the dependent variable. We kept the speed of the cart on medium, and calculated the acceleration and motion. As a result, we had figured out that the bigger the mass the slower the acceleration, as we all should have known. To calculate this we used the second law of Newton (F=ma). For the first experiment we got . 233 (m/s/s) with a percent error of 76%. The relationship for the first experiment was inverse because the acceleration was decreasing every time the weight (mass) increased. In the second experiment we got 3. 52 (m/s/s) with a percent error of 56. 4%. For this experiment the relationship was linear because the mass was increased for each trial. Some errors that could have taken place would be, cart alignment, track damaged, placement of the motion sensor. These can affect the data because it will give a greater percentage error.